The essential condition of placing the two masses, so that the system becomes dynamically equivalent, is (where l1 and l2 = Distance of two masses from the centre of gravity of the body, and kG = Radius of gyration of the body)-A-l1 = kGB-l2 = kGC-l1l2 = kGD-l1l2 = kG2-D-l1l2 = kG2

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D l1l2 = kG2 Explanation: No answer description is available.

Theory of machines - Engineering

The essential condition of placing the two masses, so that the system becomes dynamically equivalent, is (where l₁ and l₂ = Distance of two masses from the centre of gravity of the body, and k_G = Radius of gyration of the body)

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Theory of machines - Engineering

The essential condition of placing the two masses, so that the system becomes dynamically equivalent, is (where l1 and l2 = Distance of two masses from the centre of gravity of the body, and kG = Radius of gyration of the body)

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The essential condition of placing the two masses, so that the system becomes dynamically equivalent, is (where l₁ and l₂ = Distance of two masses from the centre of gravity of the body, and k_G = Radius of gyration of the body)

For help Students Orientation
Mcqs Questions