The flow of water (mass density = 1000 kg/m3 and kinematic viscosity = 10-6 m2/s) in a commercial pipe, having equivalent roughness ks as 0.12 mm, yields an average shear stress at the pipe boundary = 600 N/m2. The value of ks/δ' (δ' being the thickness of laminar sub-layer) for this pipe is-A-0.25B-0.50C-6.0D-8.0-D-8.0

Question

The flow of water (mass density = 1000 kg/m3 and kinematic viscosity = 10-6 m2/s) in a commercial pipe, having equivalent roughness ks as 0.12 mm, yields an average shear stress at the pipe boundary = 600 N/m2. The value of ks/&delta;&#39; (&delta;&#39; being the thickness of laminar sub-layer) for this pipe is-A-0.25B-0.50C-6.0D-8.0-D-8.0

APTITUDE CRACK · Accepted Answer

D 8.0 Laminar sub layer thick = 11.6 * kinematic viscosity/shear velocity. Shear velocity =(shear stress /density of fluid)^0.5.

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The flow of water (mass density = 1000 kg/m³ and kinematic viscosity = 10^-6 m²/s) in a commercial pipe, having equivalent roughness k_s as 0.12 mm, yields an average shear stress at the pipe boundary = 600 N/m². The value of k_s/δ' (δ' being the thickness of laminar sub-layer) for this pipe is

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The flow of water (mass density = 1000 kg/m3 and kinematic viscosity = 10-6 m2/s) in a commercial pipe, having equivalent roughness ks as 0.12 mm, yields an average shear stress at the pipe boundary = 600 N/m2. The value of ks/δ' (δ' being the thickness of laminar sub-layer) for this pipe is

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