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Inductors - Engineering

Q1:

The following coils are in parallel: 75 H, 40 H, 25 H, and 15 H. The total inductance is approximately

A 6.9 H

B 14 H

C 2.2 H

D 155 H

ANS:A - 6.9 H

1/L = 1/L1+1/L2+1/L3+1/L4.

1/L = 1/75+1/40+1/25+1/15.
1/L = 0.013+0.025+0.04+0.066.

1/L = 0.144.

L = 1/0.144.
L = 6.9.