Series Circuits - Engineering

Q1:

The following resistors (one each) are connected in a series circuit: 470 , 680 , 1 k, and 1.2 k. The voltage source is 20 V. Current through the 680  resistor is approximately

A 60 mA

B 30 mA

C 6 mA

D 300 mA

ANS:C - 6 mA

Tr=470+680+1000+1200.
Tr=3350.
I=v÷r.
I=20÷3350.
I=0.006.
I=6mA.