Chemical Engineering Basics

Q1: The heat released by cooling one mole of copper from 400 K to room temperature (300 K) is (assume : Cp of copper is 23 J K-1mole-1)

A 2300 J

B 4600 J

C 230 J

D 2.3 x 106 J

ANS:A - 2300 J

Q = mCp(ΔT).
Q = 1*23*(400-300),
Q = 2300.



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