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Problems on HCF and LCM - General Aptitude

Q1:

The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

A 74

B 94

C 184

D 364

ANS:D - 364

L.C.M. of 6, 9, 15 and 18 is 90. Let required number be 90k + 4, which is multiple of 7. Least value of k for which (90k + 4) is divisible by 7 is k = 4.  Required number = (90 x 4) + 4   = 364.