Problems on HCF and LCM

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

A 504

B 536

C 544

D 548

ANS:D - 548

Required number = (L.C.M. of 12, 15, 20, 54) + 8 = 540 + 8 = 548.

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