Download Aptitude Crack
img not found img not found

Strength of Materials

Q1:

The maximum diameter of the hole that can be punched from a plate of maximum shear stress 1/4th of its maximum crushing stress of punch, is equal to (where t = Thickness of the plate)

A t

B 2t

C 4t

D 8t

ANS:C - 4t

We know that Shearing pull Ps = pie/4* d^2*τ.
Therefore tao(shear stress) = 4Ps/pie d^2.

Same, crushing pull Pc = d*t*σ.
Therefore σ (crushing stress) = Pc/dt.

Now, as per question τ = 1/4 σ.
Solving this, we found d = 16/π *t.

So, dmax = 5.06t its coming, taking nearer value, its 4t.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.