Download Aptitude Crack
img not found img not found

Theory of Structures - Engineering

Q1:

The maximum magnitude of shear stress due to shear force F on a rectangular section of area A at the neutral axis, is

A

B

C

D

ANS:C -

J max=FA Y/IZ.
A = b(d/2-y).
Y BAR = {1/2(d/2+y)+y}
Z = b
I = be^3/12.

Jmax-6F{(d/2)^2-y^2}/bd^3.

Here y = 0,
Then;
Jmax = 6Fd^2/4bd^3.
Jmax = 3F/2A.