Download Aptitude Crack
img not found img not found

Theory of Structures

Q1:

The maximum magnitude of shear stress due to shear force F on a rectangular section of area A at the neutral axis, is

A

B

C

D

ANS:C -

J max=FA Y/IZ.
A = b(d/2-y).
Y BAR = {1/2(d/2+y)+y}
Z = b
I = be^3/12.

Jmax-6F{(d/2)^2-y^2}/bd^3.

Here y = 0,
Then;
Jmax = 6Fd^2/4bd^3.
Jmax = 3F/2A.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.