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Theory of Structures - Engineering

Q1:

The moment of inertia of a triangular section (height h, base b) about its base, is

A

B

C

D

ANS:C -

I(triangle about centroid) = (b*h^3÷36).
I(triangle about base) = (b*h^3÷36) + Ar^2.
Where r is the perpendicular distance between the base and centroid (h/3 in a triangle),
I(triangle about base) = (b*h^3÷36) + (1/2*bh)*(h/3)^2,
Option C = (b*h^3÷12).