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Applied Mechanics - Engineering

Q1:

The moment of inertia of the shaded portion of the area shown in below figure about the X-axis, is

A 229.34 cm4

B 329.34 cm4

C 429.34 cm4

D 529.34 cm4.

ANS:C - 429.34 cm4

Triangle moment of Inertia = (B*h^3)/12 = (8*8^3)/12.
Semicircle = (π*R^4)/8 = (π*4^4)/8.
Circle = (π*R^4)/4=(π*2^4)/4.