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Applied Mechanics - Engineering

Q1:

The motion of a particle is described by the relation x = t2- 10t + 30, where x is in metres and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be

A zero

B 30 m

C 50 m

D 60 m

E none of these.

ANS:A - zero

V= t^2 - 10t + 30.
dv/dx = 2t - 10.

If t=0,
So 2 x 0 - 10 = -10.

If t = 10,
So 2 x 10 - 10 = 20 - 10 = 10.

Total distance 10-10 = 0 Answer.