The normal component of a force inclined through θ° is obtained by multiplying the force by-A-sin θB-cos θC-tan θD-sin θ cos θE-sin2θ-D-sin θ cos θ

Question

The normal component of a force inclined through &theta;&deg; is obtained by multiplying the force by-A-sin &theta;B-cos &theta;C-tan &theta;D-sin &theta; cos &theta;E-sin2&theta;-D-sin &theta; cos &theta;

APTITUDE CRACK · Accepted Answer

D sin &theta; cos &theta; Not understanding this. please explain to me.

Theory of Structures - Engineering

The normal component of a force inclined through θ° is obtained by multiplying the force by

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Theory of Structures - Engineering

The normal component of a force inclined through θ° is obtained by multiplying the force by

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