The OH^- concentration in a solution having pH value 3 is

ANS:C - 10^-11

The pH of a solution is defined as the negative logarithm of the concentration of hydrogen ions (𝐻+H+) in the solution. Mathematically, it's represented as: pH=−log⁡[𝐻+]pH=−log[H+] For a neutral solution (𝑝𝐻=7pH=7), the concentration of 𝐻+H+ ions is 10−710−7 M. In an acidic solution (pH less than 7), the concentration of 𝐻+H+ ions is higher than 10−710−7 M. Given that the pH of the solution is 3, which is acidic, the concentration of 𝐻+H+ ions is higher than 10−710−7 M. pH=−log⁡[𝐻+]pH=−log[H+] 3=−log⁡[𝐻+]3=−log[H+] Solving for [𝐻+][H+]: [𝐻+]=10−3[H+]=10−3 The 𝑂𝐻−OH− concentration in a solution can be calculated using the relationship: [𝐻+]×[𝑂𝐻−]=10−14[H+]×[OH−]=10−14 Given that [𝐻+]=10−3[H+]=10−3, we can calculate [𝑂𝐻−][OH−]: 10−3×[𝑂𝐻−]=10−1410−3×[OH−]=10−14 [𝑂𝐻−]=10−1410−3[OH−]=10−310−14​ [𝑂𝐻−]=10−11[OH−]=10−11 So, the 𝑂𝐻−OH− concentration in the solution with a pH of 3 is 10−1110−11. Therefore, the correct option is: 10^-11