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RLC Circuits and Resonance

Q1:

The output voltage at the resonant frequency is ______ in the given circuit. If a 10 komega.gif load is connected.

A 553 mV

B 5.65 V

C 6.01 V

D 6.5 V
 

ANS:B - 5.65 V

First step is to obtain the resonance frequency.
1.) (fr), XL = XC --> 2*pi*fr*L = 1/ 2*pi*fr*C --> fr = 25342 Hz.
2.) XL = XC --> 923.55.
3.) (XL + R) // XC --> 11409.99<-4.64 ohms.
4.) 5333.64 // 10k --> 5333.64<-2.17.
5.) Voltage divider formula: (6.5 * 5333.64<-2.17) / (5333.64<-2.17+800).
Answer: 5.65 Volts.



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