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Series-Parallel Circuits - Engineering

Q1:

The parallel combination of a 470  resistor and a 1.5 k resistor is in series with the parallel combination of five 1 k resistors. The source voltage is 50 V. The percentage of the load current through any single 1 k resistor is

A 25%

B 20%

C 100%

D 50%

ANS:B - 20%

Five 1k ohm parrallel R=200..
i =V/R =50/200=0.25.
i for 1k, i = 50/1000 = 1/20 = 0.05.
i %=0.05 * 100/0.25 = 20%.