Q1: The parallel combination of a 6.8 k resistor and a 10 k resistor is in series with the parallel combination of a 2.2 k resistor and a 1 k resistor. A 100 V source is connected across the circuit. The resistor(s) with the greatest voltage drop is (are)

ANS:C - 6.8 k and 10 k

(6.8k * 10k)/(6.8k + 10k) = 4.047k ohms.
(2.2k * 1k)/(2.2K + 1K) = 687.5 ohms.

Now 4.047 k ohms is in series with 687.5 ohms.
FOR SERIES current is same through out the circuit so P = I^2 R.
More the R, more is the voltage drop (power dissipation) so more voltage drop in parallel combination of 6.8k and 10k.