The piston of a steam engine moves with a simple harmonic motion. The crank rotates 120 r.p.m. and the stroke length is 2 metres. The linear velocity of the piston when it is at a distance of 0.5 metre from the centre, is

ANS:C - 10.88 m/sec

Given: N = 120 R.P.M. or ω = 2*120/60 = 4 rad/s ; 2r = 2 m or r = 1 m;

x = 0.5 m.

Velocity of the piston. We know that velocity of the piston,

Linear velocity, v = ω r^2/x^2 2^2/(0.5)^2 = 10.88 m/s Answer.