The pressure of 'V' litres of a dry gas is increased from 1 to 2 kgf/cm² at a constant temperature. The new volume will become

ANS:A - V/2

To solve this problem, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional when the temperature remains constant. Mathematically, Boyle's law is expressed as: 𝑃1⋅𝑉1=𝑃2⋅𝑉2P1​⋅V1​=P2​⋅V2​ Where:

• 𝑃1P1​ and 𝑉1V1​ are the initial pressure and volume, respectively.
• 𝑃2P2​ and 𝑉2V2​ are the final pressure and volume, respectively.

Given that the initial pressure (𝑃1P1​) is 1 kgf/cm22, the final pressure (𝑃2P2​) is 2 kgf/cm22, and the initial volume (𝑉1V1​) is 𝑉V liters, we can solve for the final volume (𝑉2V2​). 𝑃1⋅𝑉1=𝑃2⋅𝑉2P1​⋅V1​=P2​⋅V2​ 1×𝑉=2×𝑉21×V=2×V2​ 𝑉2=𝑉2V2​=2V​ Therefore, the new volume (𝑉2V2​) will become 𝑉22V​. So, the correct option is 𝑉/2V/2.