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Problems on HCF and LCM - General Aptitude

Q1:

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

A 101

B 107

C 111

D 185

ANS:C - 111

Let the numbers be 37a and 37b. Then, 37a x 37b = 4107  ab = 3. Now, co-primes with product 3 are (1, 3). So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).  Greater number = 111.