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Capacitors - Technical MCQs

Q1:

The reactance of C2 is _____ in the given circuit.

A 66 omega.gif

B 80 omega.gif

C 199 omega.gif

D 398 omega.gif

ANS:D - 398 omega.gif

Total c=(2*(5+1))/(2+5+1) = 1.5.

R(total) = 1/(2*3.14*1.5*10^6) = 265.15.

Now r1/(r2||r3) = (c2||c3)/c1.

Therefore r1/(r2||r3) = 6/2 = 3.
Therefore (r2||r3) = r/(r1+r2||r3) = 265.15/4 = 66.28.

Now again r2/r3 = c3/c2.
Thus r2 = (r2||r3)* (c3+c2)/c2 = 66.28 *6 /1 = 397.68 == 398.