The relation among various mass transfer co-efficients (M.T.C) for ideal gases is given by (where, Kc & Km are M.T.C. for equimolar counter diffusion with concentration & mole fraction respectively as the driving force. and, Kp = M.T.C. for diffusion of a gas through a stagnant inert gas with pressure as driving force.)-A-Kc = Kp = KmB-Kc = Kp/RT = Km . RT/PC-Kc = Kp . RT = Km . RT/pD-none of these-C-Kc = Kp . RT = Km . RT/p

Question

The relation among various mass transfer co-efficients (M.T.C) for ideal gases is given by (where, Kc &amp; Km are M.T.C. for equimolar counter diffusion with concentration &amp; mole fraction respectively as the driving force. and, Kp = M.T.C. for diffusion of a gas through a stagnant inert gas with pressure as driving force.)-A-Kc = Kp = KmB-Kc = Kp/RT = Km . RT/PC-Kc = Kp . RT = Km . RT/pD-none of these-C-Kc = Kp . RT = Km . RT/p

APTITUDE CRACK · Accepted Answer

The correct option is  C Kc = Kp . RT = Km . RT/p The relation among various mass transfer coefficients (M.T.C) for ideal gases is given by: &#119870;&#119888;=&#119870;&#119901;=&#119870;&#119898;Kc​=Kp​=Km​ This equation states that for ideal gases, the mass transfer coefficients for equimolar counter diffusion with concentration (&#119870;&#119888;Kc​), for diffusion of a gas through a stagnant inert gas with pressure as the driving force (&#119870;&#119901;Kp​), and for equimolar counter diffusion with mole fraction (&#119870;&#119898;Km​) are all equal. Therefore, the correct option is: &#119870;&#119888;=&#119870;&#119901;=&#119870;&#119898;Kc​=Kp​=Km​.

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