The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the lengm of connecting rod to radius of crank)-A-m.ω2.r sin θB-m.ω2.r cos θC-m.ω2.r D-m.ω2.r -D-m.ω2.r

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The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, &omega; = Angular speed of crank, r = Radius of crank, &theta; = Angle of inclination of crank with the line of stroke, and n = Ratio of the lengm of connecting rod to radius of crank)-A-m.&omega;2.r sin &theta;B-m.&omega;2.r cos &theta;C-m.&omega;2.r D-m.&omega;2.r -D-m.&omega;2.r

APTITUDE CRACK · Accepted Answer

The correct option is  D m.&omega;2.r  Explanation: No answer description is available.

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