The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the lengm of connecting rod to radius of crank)-A-m.ω2.r sin θB-m.ω2.r cos θC-m.ω2.r D-m.ω2.r -D-m.ω2.r

Question

The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, &omega; = Angular speed of crank, r = Radius of crank, &theta; = Angle of inclination of crank with the line of stroke, and n = Ratio of the lengm of connecting rod to radius of crank)-A-m.&omega;2.r sin &theta;B-m.&omega;2.r cos &theta;C-m.&omega;2.r D-m.&omega;2.r -D-m.&omega;2.r

APTITUDE CRACK · Accepted Answer

D m.&omega;2.r  Explanation: No answer description is available.

Theory of machines

For help Students Orientation
Mcqs Questions

Quick Links

Newsletter

Theory of machines

Solution

For help Students Orientation Mcqs Questions

For help Students Orientation
Mcqs Questions