Q1:

The shear force diagram of a beam is shown in the given figure. The absolute maximum bending moment in the beam is

ANS:B - (5P x a)

Position taken from ->

1st position =5unit downward
2nd position=12 unit upward
3rd posirion=9 unit downrd
4th position =4 unit upward
5th position = 2 unit downward

Now, calculate BM from LHS as u can see 5*a gives Max bm at 2nd position. You can also calculate from RHS side you will get the same result.