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Problems on HCF and LCM

Q1: The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

A 1008

B 1015

C 1022

D 1032

ANS:B - 1015

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7    = 1008 + 7    = 1015



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