

Problems on HCF and LCM - General Aptitude
Q1: The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:A 1008
B 1015
C 1022
D 1032
ANS:B - 1015 Required number = (L.C.M. of 12,16, 18, 21, 28) + 7 = 1008 + 7 = 1015 |


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