Surveying

Q1: The staff reading at a distance of 80 m from a level with the bubble at its centre is 1.31 m. When the bubble is moved by 5 divisions out of the centre, the reading is 1.39 m. The angular value of the one division of the bubble, is

A 28.8 secs

B 41.25 secs

C 14.52 secs

D 25.05

E none of these

ANS:B - 41.25 secs

We know angular value, α =( S/nD) * 206265.

Here.
S = Staff intercept = 1.39 - 1.31 = 0.08 meter.
n = number of division given for change in reading = 5 divisions.
D = linear distance between instrument and Staff = 80 meter.
& multiplied by 206265 to convert an angular value from radian to seconds.

Put the values and answer will be 41.253 seconds per division. 1 degree = 3600 sec.
1 radian =180 degree =57.2958°.
1 radian = 206265" second. 206265 = s/d.

s = 1.39-1.31 = 0.08 m/5 div.

= (206265*0.08)/80.

= 206.265 sec/5 div.

= (206.265*1)/5.

= 41.253 sec/1 div.

Answer B.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.