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Theory of Structures - Engineering

Q1:

The stiffness of the close coil helical spring is

A

B

C

D

ANS:A -

Deflection= 64w (r^3) n/Nd^4 where stiffness= load/deflection load p = w.

We know that radius r = D/2 and substitute i.e. deflection = 64w (D/2) ^3n/Nd^4=64wD^3n/8Nd^4.

= 8wD^3n/Nd^4.

Now stiffness = load/deflection = w/ (8wD^3n/Nd^4) = nd^4N/8D^3n.