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Chemical Engineering Basics

Q1:

The thermal efficiency of a heat engine giving an output of 4 KW with an input of 10000 Joules/sec is __________ percent.

A 40

B 80

C 10

D 25

ANS:A - 40

To calculate the thermal efficiency (η) of a heat engine, we use the formula: η=Input EnergyUseful Output Energy​×100% Given:

  • Useful Output Energy (output of the heat engine) = 4 kW
  • Input Energy (input to the heat engine) = 10000 J/s = 10 kW
Now, we'll plug these values into the formula: η=10 kW4 kW​×100% η=104​×100% η=0.4×100% η=40% So, the thermal efficiency of the heat engine is 40%40%. Therefore, the correct answer is 40 percent.



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