The total number of atoms in 8.5 gm of NH₃ is __________ x 10²³.

ANS:A - 9.03

To find the total number of atoms in 8.5 g8.5g of 𝑁𝐻3NH3​, we'll first calculate the number of moles of 𝑁𝐻3NH3​ using its molar mass and then use Avogadro's number (6.02×10236.02×1023) to convert moles to atoms. The molar mass of 𝑁𝐻3NH3​ is the sum of the atomic masses of nitrogen (𝑁N) and three times the atomic mass of hydrogen (𝐻H): Molar mass of NH3=14.01 g/mol+3×1.008 g/molMolar mass of NH3​=14.01g/mol+3×1.008g/mol Molar mass of NH3=17.03 g/molMolar mass of NH3​=17.03g/mol Now, we'll calculate the number of moles of 𝑁𝐻3NH3​ in 8.5 g8.5g: Number of moles=MassMolar massNumber of moles=Molar massMass​ Number of moles=8.5 g17.03 g/molNumber of moles=17.03g/mol8.5g​ Number of moles≈0.498 molNumber of moles≈0.498mol Now, to find the total number of atoms, we'll use Avogadro's number: Total number of atoms=Number of moles×Avogadro’s numberTotal number of atoms=Number of moles×Avogadro’s number Total number of atoms≈0.498 mol×6.02×1023 atoms/molTotal number of atoms≈0.498mol×6.02×1023atoms/mol Total number of atoms≈3.0×1023 atomsTotal number of atoms≈3.0×1023atoms So, the total number of atoms in 8.5 g8.5g of 𝑁𝐻3NH3​ is approximately 3.0×10233.0×1023 atoms. Therefore, the answer is 3.013.01​ multiplied by 10231023.