Series Circuits - Engineering

Q1:

The total resistance of eight 5.6 k resistors in series is

A

B 5,600 

C 4,480 

D 44,800 

ANS:D - 44,800 

R= R1+R2+R3+R4+R5+R6+R7+R8
R=5.6+5.6+5.6+5.6+5.6+5.6+5.6+5.6
R=44.8K Ohm
R=44.8*1000
R=44800 Ohm