The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then RB =-A-200 kΩB-265 kΩC-150 kΩD-100 kΩ-B-265 kΩ

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The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then RB =-A-200 k&Omega;B-265 k&Omega;C-150 k&Omega;D-100 k&Omega;-B-265 k&Omega;

APTITUDE CRACK · Accepted Answer

The correct option is  B 265 k&Omega;  .

Analog Electronics

Q1:
The transistor of following figure in Si diode with a base current of 40 μA and I_CBO = 0, if V_BB = 6V, R_E = 2 kΩ and β = 90, I_BQ = 20 μA then R_B =

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Analog Electronics

Q1: The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then RB =

Solution

For help Students Orientation Mcqs Questions

Q1:
The transistor of following figure in Si diode with a base current of 40 μA and I_CBO = 0, if V_BB = 6V, R_E = 2 kΩ and β = 90, I_BQ = 20 μA then R_B =

For help Students Orientation
Mcqs Questions