The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then IEQ =-A-1800 μAB-180 μAC-2000 μAD-3000 μA-A-1800 μA

Question

The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then IEQ =-A-1800 &mu;AB-180 &mu;AC-2000 &mu;AD-3000 &mu;A-A-1800 &mu;A

APTITUDE CRACK · Accepted Answer

A 1800 &mu;A  , ICQ = β IBQ = 90 x 20 μA = 1800 μA.

Analog Electronics

The transistor of following figure in Si diode with a base current of 40 μA and I_CBO = 0, if V_BB = 6V, R_E = 2 kΩ and β = 90, I_BQ = 20 μA then I_EQ =

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Analog Electronics

The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then IEQ =

Solution

For help Students Orientation Mcqs Questions

The transistor of following figure in Si diode with a base current of 40 μA and I_CBO = 0, if V_BB = 6V, R_E = 2 kΩ and β = 90, I_BQ = 20 μA then I_EQ =

For help Students Orientation
Mcqs Questions