The velocity of a body fallen from height h, on reaching the ground is given by-A-v = 2ghB-v = 2gh2C-v = 2ghD-v = 1/2ghE-h2/2g-C-v = 2gh

Question

APTITUDE CRACK · Accepted Answer

C v = 2gh Law conservation of energy is applicable. initial = final. (PE)i + (KE)i = (PE)f + (KE)f. mgh + ( 0) = (0)+ 1/2 mv^2.

Applied Mechanics - Engineering