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Magnetism and Electromagnetism - Engineering

Q1:

The voltage induced across a certain coil is 200 mV. A 120  resistor is connected to the coil terminals. The induced current is

A 1.7 mA

B 16 mA

C 12 mA

D 120 mA

ANS:A - 1.7 mA

I=V/R

Here the voltage induce in that coil =200mv
The resistor connected by parallel =120
So the resultant current =
200/120=1.66mA or 1.7mA