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Ohm's Law

Q1:

The voltage supplying the current in the given circuit is _____.

A 2.5 V

B 25 V

C 250 V

D 2.5 kV

ANS:B - 25 V

V = IR

= 250 x 10^-6 x 100 x 10^3

= 250 x 100 x 10^(-6+3)

= 250 x 100 x 10^-3

= 25 x 1000 x 10^-3

= 25 x 10^3 x 10^-3

= 25 x 10^0

= 25 x 1 [Anything power 0 is 1]

= 25 volts.



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