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UPSC Civil Service Exam Questions

Q1:

The weight of aggregate having specific gravity 2.65, completely filled into a cylinder of volume 0.003 m3 is 5.2 kg. What is the value of the angularity index of aggregate (approximately) as given by Murdock ?

A 1

B 0.34

C 0.15

D 0.05

ANS:B - 0.34

Specific gravity = 2.65.
v = .003
wt = 5.2kg
Vs = 5.2/(2.65*10^3)=0.0019
Vv = V-Vs
Vv = 0.003-0.0019 = 0.0011.
Angularity index = Vv/V.
=.0011/.003 = .37 (.35 approx)
So, option B is correct.



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