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Parallel Circuits - Engineering

Q1:

There is a total of 800 mA of current into four parallel resistors. The currents through three of the resistors are 40 mA, 70 mA, and 200 mA. The current through the fourth resistor is

A 490 mA

B 800 mA

C 310 mA

D 0 A

ANS:A - 490 mA

Total current=sum of the current across parallel circuit,
800=40+70+200-I,so
I=800-(40+70+200)=800-310=490 MA