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Series-Parallel Circuits - Engineering

Q1:

Three 10 k resistors are connected in series. A 20 k resistor is connected in parallel across one of the 10 k resistors. The voltage source is 24 V. The total current in the circuit is

A 900 A

B 9 mA

C 90 mA

D 800 A

ANS:A - 900 A

across one of the resistors 20 ohms placed in parallel .so solving parallel formula
R1*R2/R1+R2=>20*10/20+10=6.66 .

Other two resisters with parallel solved value =6.66+10+10=26.66.

I=V/R => 24/26.66=900*10^-6.