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Q1:
Time domain equivalent circuit of the figure is

A

B

C

D None of the above

ANS:A -

In the left hand loop (- i1) enters the dot end while for the right handed loop i2 enters the dot end. This will make both the M terms at first of + ve sign but as i1 = - ve hence ultimately the M term of right hand loop involving i1 = - ve. V1 = - L1 + M V2 = L2 - M .



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