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Capacitors - Engineering

Q1:

Two 0.68 F capacitors are connected in series across a 10 kHz sine wave signal source. The total capacitive reactance is

A 46.8 

B 4.68 

C 23.41 

D 11.70 

ANS:A - 46.8 

C= c1*c2/ (c1+c2)
= .68*.68/ (.68+.68)
= .34microfarad.

Xc = 1/2π*f*c
= 1/ (2π*10k*.34microfarad),
= 46.8ohm.