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Series Circuits - Engineering

Q1:

Two 6 V batteries are connected series aiding across two 1.2 k resistors in series. Current through each resistor is

A 5 mA

B 10 mA

C 0 A

D 2.5 mA

ANS:A - 5 mA

Series aiding means 6v + 6V+ 12 v.

Total current = 12v/2.4 k ohm = 5 milli amp.

Since two 1.2 K ohm in series, current will be same in both resistors.