Electronic Devices and Circuits - Engineering

Q1:

Two identical silicon diodes D1 and D2 are connected back to back shown in figure. The reverse saturation current Is of each diode is 10-8 amps and the breakdown voltage VBr is 50 v. Evaluate the voltages VD1 and VD2 dropped across the diodes D1 and D2 assuming KT/q to be 25 m V.

A 4.983 V, 0.017 V

B - 4.98 V, - 0.017 V

C 0.17 V, 4.983 V

D - 0.017 V, - 4.98 V

ANS:B - - 4.98 V, - 0.017 V

According to figure, D2 is forward bias, D1 is reverse biased. Reverse saturation current I0 = 10-8A. in clockwise direction. For Diode D2 Is = I0 Here Is = I0 eqv2/kT = 2 or ev2/0.026 = 2 V2 = 0.018 V Drop across D1 = V1 = 5 - 0.018 4.98 V By KVL in mesh, VD1 = -4.98 V, VD2 = 0.018 V.