- UPSC Civil Service Exam Questions - Section 1
- UPSC Civil Service Exam Questions - Section 2
- UPSC Civil Service Exam Questions - Section 3
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- UPSC Civil Service Exam Questions - Section 11
- UPSC Civil Service Exam Questions - Section 12
- UPSC Civil Service Exam Questions - Section 13
- UPSC Civil Service Exam Questions - Section 14
- UPSC Civil Service Exam Questions - Section 15
- UPSC Civil Service Exam Questions - Section 16
- UPSC Civil Service Exam Questions - Section 17
- UPSC Civil Service Exam Questions - Section 18
- UPSC Civil Service Exam Questions - Section 19
- UPSC Civil Service Exam Questions - Section 20
- UPSC Civil Service Exam Questions - Section 21
- UPSC Civil Service Exam Questions - Section 22
- UPSC Civil Service Exam Questions - Section 23
- UPSC Civil Service Exam Questions - Section 24
- UPSC Civil Service Exam Questions - Section 25
- UPSC Civil Service Exam Questions - Section 26
- UPSC Civil Service Exam Questions - Section 27


UPSC Civil Service Exam Questions - Engineering
Q1: Two men, one stronger than the other have to lift a load of 1200 N which is suspended from a light rod of length 3 m. The load is suspended between the two persons positioned at the two ends of the rod. The weaker of the two persons can carry a load up to 400 N only. The distance of the load to be suspended from the stronger person such that the weaker person has the full share of 400 N isA 0.5 m
B 1.0 m
C 1.5 m
D 2.0 m
ANS:D - 2.0 m The weight is divided between the two persons and so will become 400N for the weak person and 1200-400=800N for the stronger one.now by taking moment at strong person side we get the equation as: |


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