Two resistances are : R1 = 36 Ω ± 1.89 Ω and R2 = 75 Ω ± 3.75 Ω. The sum R1 + R2 along with limiting error is-A-111 Ω ± 1.8 ΩB-111 Ω ± 3.75 ΩC-111 Ω ± 5.55 ΩD-111 Ω ± 1.95 Ω-C-111 Ω ± 5.55 Ω

Question

Two resistances are : R1 = 36 &Omega; &plusmn; 1.89 &Omega; and R2 = 75 &Omega; &plusmn; 3.75 &Omega;. The sum R1 + R2 along with limiting error is-A-111 &Omega; &plusmn; 1.8 &Omega;B-111 &Omega; &plusmn; 3.75 &Omega;C-111 &Omega; &plusmn; 5.55 &Omega;D-111 &Omega; &plusmn; 1.95 &Omega;-C-111 &Omega; &plusmn; 5.55 &Omega;

APTITUDE CRACK · Accepted Answer

C 111 &Omega; &plusmn; 5.55 &Omega; 36 + 75 = 111, 1.8 + 3.75 = 5.55. Therefore, R1 + R2 = 111 &plusmn; 5.55 ohm.

Measurements and Instrumentation - Engineering

Two resistances are : R₁ = 36 Ω ± 1.89 Ω and R₂ = 75 Ω ± 3.75 Ω. The sum R₁ + R₂ along with limiting error is

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Measurements and Instrumentation - Engineering

Two resistances are : R1 = 36 Ω ± 1.89 Ω and R2 = 75 Ω ± 3.75 Ω. The sum R1 + R2 along with limiting error is

Solution

For help Students Orientation Mcqs Questions

Two resistances are : R₁ = 36 Ω ± 1.89 Ω and R₂ = 75 Ω ± 3.75 Ω. The sum R₁ + R₂ along with limiting error is

For help Students Orientation
Mcqs Questions