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Alternating Current and Voltage - Engineering

Q1:

Two series resistors are connected to an ac source. If there are 7.5 V rms across one resistor and 4.2 V rms across the other, the peak source voltage is

A 16.54 V

B 1.65 V

C 10.60 V

D 5.93 V

ANS:A - 16.54 V

Drop accross series resistor = 7.5+4.2 = 11.7Vrms.
Vrms = 0.707*Vp.
Vp = Vrms/0.707.
= 11.7/0.707 = 16.54V.