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Applied Mechanics - Engineering

Q1:

Two shots fired simultaneously from the top and bottom of a vertical tower with elevations of 30° and 45° respectively strike a target simultaneously. If horizontal distance of the target from the tower is 1000 m, the height of the tower is

A 350 m

B 375 m

C 400 m

D 425 m.

ANS:D - 425 m.

1/3 * 3/2 * 1000 = 500.

Now we have two angle 30 + 45 = 75, 500 - 75, 425.