- Chemical Engineering Basics - Section 1
- Chemical Engineering Basics - Section 2
- Chemical Engineering Basics - Section 3
- Chemical Engineering Basics - Section 4
- Chemical Engineering Basics - Section 5
- Chemical Engineering Basics - Section 6
- Chemical Engineering Basics - Section 7
- Chemical Engineering Basics - Section 8
- Chemical Engineering Basics - Section 9
- Chemical Engineering Basics - Section 10
- Chemical Engineering Basics - Section 11
- Chemical Engineering Basics - Section 12
- Chemical Engineering Basics - Section 13
- Chemical Engineering Basics - Section 14
- Chemical Engineering Basics - Section 15
- Chemical Engineering Basics - Section 16
- Chemical Engineering Basics - Section 17
- Chemical Engineering Basics - Section 18
- Chemical Engineering Basics - Section 19
- Chemical Engineering Basics - Section 20
- Chemical Engineering Basics - Section 21
- Chemical Engineering Basics - Section 22
- Chemical Engineering Basics - Section 23
- Chemical Engineering Basics - Section 24
- Chemical Engineering Basics - Section 25
- Chemical Engineering Basics - Section 26
- Chemical Engineering Basics - Section 27
- Chemical Engineering Basics - Section 28


Chemical Engineering Basics - Engineering
Q1: Two wires of the same radius & material having length in the ratio of 1 : 2 are stretched by the same force. The strain produced in the two wires will be in the ratio ofA 1:1
B 1:2
C 2:1
D 1:4
ANS:A - 1:1 The strain produced in a wire is directly proportional to the force applied and inversely proportional to the cross-sectional area of the wire. Since the wires in question have the same material and are stretched by the same force, the ratio of their strains will depend only on their lengths. Given that the lengths of the wires are in the ratio of 1:1, we can assume that the longer wire experiences twice the elongation compared to the shorter wire for the same force. Therefore, the ratio of their strains will also be in the ratio of 1:2. So, the correct answer is 1:1 |


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