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Computer Fundamentals

Q1:

What is the byte capacity of a drum which is 5 inch high, 10 inch diameter, and which has 60 tracks per inch and bit density of 800 bits per inch?

A 942000 bytes

B 9712478 bytes

C 192300 bytes

D 14384 bytes

E None of the above

ANS:A - 942000 bytes

Total capacity = (areal density)*(total surface area).

Areal density = 60*800=48000 bits per inch.

Total surface area = 2*pi*r*h=2*pi*5*5=50*pi.

Total capacity = (50*3.14*48000)/8=942000 bytes.



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