What is the flux density when the flux is 5.5 Wb and the cross-sectional area is 6 × 10^–3 m²?

ANS:B - 917 T

Lets solve it
We have given flux density=5.5*10^-6 wb
And cross sectional area= 6*10^-3 m^2

We take
B=Q/A
B=flux density in tesla(T)
Q=magnetic flux in weber(wb)
A=cross section area in square metre

B=5.5*10^-6/6*10^-3 =(5.5*10-3)/6 =0.9166666 *10^-3

If you round of then you will be get

B=917microT ANS