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RLC Circuits and Resonance - Technical MCQs

Q1:

What is the impedance of the circuit in the given circuit?

A 1.05 komega.gif

B 1.33 komega.gif

C 2.19 komega.gif

D 3.39 komega.gif

ANS:A - 1.05 komega.gif

r=1.2K ohms.
Xl=2*π*f*L = 423π ohms.

So, Xc = 1/(2*π*f*C) = 3386.275385 ohms.

For parallel circuit:
Y = G+i(Bc-Bl).

Where:
G = 1/r.
Bc = 1/Xc,
Bl = 1/Xl.

Finally, solving for Impedance

Z = 1/Y
Z = 1052.064861 ohms or 1.052k ohms.